(pᵃ/pᵇ)ᵃ⁺ᵇ = (p-q)⁽ᵃ⁺ᵇ⁾⁽ᵃ⁻ᵇ⁾
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to prove : (pᵃ/pᵇ)ᵃ⁺ᵇ = (p)⁽ᵃ⁺ᵇ⁾⁽ᵃ⁻ᵇ⁾
proof : (\frac{p^a}{p^b})^a^+^b
(p^a^-^b)^a^+^b
p^(^a^-^b^)^(^a^+^b^)
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