Question

(pᵃ/pᵇ)ᵃ⁺ᵇ = (p-q)⁽ᵃ⁺ᵇ⁾⁽ᵃ⁻ᵇ⁾

|| prove ||​

Answer 1

to prove : (pᵃ/pᵇ)ᵃ⁺ᵇ = (p)⁽ᵃ⁺ᵇ⁾⁽ᵃ⁻ᵇ⁾

proof : $(\frac{p^a}{p^b})^a^+^b$

$(p^a^-^b)^a^+^b$

$p^(^a^-^b^)^(^a^+^b^)$