Science, asked by s1044mholyashubhan25, 4 months ago

P+p²+p³+p⁴+p⁵+p⁶+p⁷)/(p⁻³+p⁻⁴+p⁻⁵+p⁻⁶+p⁻⁷+p⁻⁸+p⁻⁹)​

Answers

Answered by nivedhan120405
14

Answer:

hope it helps you

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Answered by pkmkb93000
5

\underline \pink{\textsf{Given:}}

\bold\red{\mathsf{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}}}

\underline \green{\textsf{To find:}}\textsf \blue{The value of}

\mathsf \purple{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}} </p><p>

\underline \orange{\textsf{Solution:}}

\textsf \red{Consider,}

\mathsf \pink{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}}

\textsf \green{Multiply both numerator and denominator by}\,\mathsf{p^{10}}

\mathsf \orange{=\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}{\times}\dfrac{p^{10}}{p^{10}}}

\mathsf \blue{=\dfrac{(p+p^2+p^3+p^4+p^5+p^6+p^7)p^{10}}{p^7+p^6+p^5+p^4+p^3+p^2+p}}

\mathsf\red{=\dfrac{(p+p^2+p^3+p^4+p^5+p^6+p^7)p^{10}}{p+p^2+p^3+p^4+p^5+p^6+p^7}}

\mathsf \blue{=p^{10}}

\underline \green{\textsf{Answer:}}

\mathsf \pink{\dfrac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p^{-3}+p^{-4}+p^{-5}+p^{-6}+p^{-7}+p^{-8}+p^{-9}}=p^{10}}

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