Question

p+p²+p³+p⁴+p⁵+p⁶+p⁷)/(p‐³+p‐⁴+ p‐⁵+p‐⁶+p‐⁷+p‐⁸+p‐⁹)​

Answer 1

Step-by-step explanation:

p+p²+p³+p⁴+p⁵+p⁶+p⁷)/(p‐³+p‐⁴+ p‐⁵+p‐⁶+p‐⁷+p‐⁸+p‐⁹)

Answer 2

Multiply both numerator and denominator by p¹⁰

= $\frac{p+p^2+p^3+p^4+p^5+p^6+p^7}{p-^3+p-^4+p-^5+p-^6+p-^7-p-^8-p-^9}$  $\times\ \frac{p^1^0}{p^1^0}$

= $\frac{(p+p^2+p^3+p^4+p^5+p^6+p^7)p^1^0}{p^7+p^6+p^5+p^4+p^3+p^2+p}$

= p¹⁰