Question

(p-q)^2= 25 and pq = 14, what is the value of (p + q)^2
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Answer 1

Answer:

(p+q)² = 81

Step-by-step explanation:

(p-q)² = 25 & pq = 14

we know that,

(p+q)² = (p-q)² + 4 pq

=> (p+q)² = 25 + 4 × 14

=> (p+q)² = 25 + 56

(p+q)² = 81

Answer 2

Given:-

• (p-q)² = 25
• pq = 14

To Find:-

• (p+q)²

Solution:-

✯ (a-b)² = a²+b²-2ab

→ (p-q)² = 25

→ p²+q²-2pq = 25

→ p²+q²-2(14) = 25

→ p²+q² = 25+28

→ p²+q² = 53

✯ (a+b)² = a²+b²-2ab

→ (p+q)²

→ p²+q²+2pq

→ 53+2(14)

→ 53+28

→ 81

• Value of (p+q)² ☞ 81

Hope It Helps You ✌️