Math, asked by stutikirti5, 7 months ago

p/q= (2/3)³ × (1/3)⁴
find the value of (p/q)²​

Answers

Answered by adityaparashar1
4

Answer:

P(x) = px⁴+qx³+3x²-2x+3. When divided by x²-3x+2, P(x) = px⁴+qx³+3x²-2x+3 = Rem(x + 1). x²-3x+2 = (x-1)(x-2).

P(1) = p(1)⁴+q(1)³+3(1)²-2(1)+3 = p + q + 3 - 2 + 3 = p +

q + 4 = (1) + 1 = 2 => p + q = -2.

P(2) = p(2)⁴+q(2)³+3(2)²-2(2)+3 = 16p + 8q + 12 - 4 + 3 = 16p + 8q + 11 = (2) + 1 = 3 => 16p + 8q = -8.

p + q = -2, 16p + 8q = -8 => p = 1, q = -3

Step-by-step explanation:

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Answered by ranjana64
2

Answer:

p/q = (2/3)³ × (1/3)⁴

(p/q)² = { (2/3)³ × (1/3)⁴}²

= (2/3)⁶ × (1/3)⁸

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