Question

(p+q)²-(a-b)² factorise​

Answer 1

Step-by-step explanation:

${(p + q})^{2} - {(a - b)}^{2} \\ = [(p + q) + (a - b) ] [(p + q) - (a - b)] \\ = (p + q + a - b)(p + q - a + b)$

Answer 2

we know that (a+b)^2=a^2+b^2+2ab

and (a-b)^2=a^2+b^2-2ab

so p^2+q^2+2pq-a^2+b^2-2ab