(p-q)^3 + (q-r)^3 + (r-p)^3
FACTORIES
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Step-by-step explanation:
let,
- a = p - q
- b = q - r
- c = r - p
So, the given expression becomes,
a³ + b³ + c³
Now,
a + b + c = p - q + q - r + r - p = 0
So,
a + b + c = 0
Therefore,
a³ + b³ + c³ - 3abc = (a + b + c)(a² + b² + c² - ab - bc - ca)
Since (a + b + c) = 0,
So,
a³ + b³ + c³ - 3abc = 0
=> a³ + b³ + c³ = 3abc
Now, putting the values of a, b, c, We get,
(p - q)³ + (q - r)³ + (r - p)³ = 3(p - q)(q - r)(r - p)
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