Question

(p+q+3)square pls ans the formula (a+b+c)=a²+b²+c²+2ab+2bc+2ac​

Answer 1

$\huge{\mathfrak{\underline{\red{Answer!}}}}$

Answer:

a = b = c

Step-by-step explanation:

Given Quadratic Equation is 3x² - 2(a + b + c)x + ab + bc + ac = 0.

On comparing with ax² + bx + c = 0, we get

a = 3, b = -2(a + b + c), c = ab + bc + ac.

Given that the equation has equal roots.

∴ b² - 4ac = 0

⇒ [-2(a + b + c)]² - 4(3)(ab + bc + ac) = 0

⇒ 4(a + b + c)² - 12(ab + bc + ac) = 0

⇒ 4a² + 4b² + 4c² + 8ab + 8bc + 8ac - 12ab - 12bc - 12ac = 0

⇒ 4a² + 4b² + 4c² - 4ab - 4bc - 4ac = 0

⇒ a² + b² + c² - ab - bc - ac = 0

⇒ a² + b² + c² = ab + bc + ac

Multiply both sides by '2', we get

⇒ 2(a² + b² + c²) = 2(ab + bc + ac)

⇒ 2a² + 2b² + 2c² = 2ab + 2bc + 2ac

⇒ a² + a² + b² + b² + c² + c² = 2ab + 2bc + 2ca

⇒ a² + b² - 2ab + b² + c² - 2bc + c² + a² - 2ca = 0

⇒ (a - b)² + (b - c)² + (c - a)² = 0

⇒ a - b = 0, b - c = 0, c - a = 0

⇒ a = b, b = c, c = a

⇒ a = b = c.

Hope it helps!

Answer 2

Answer:

p square + q square + 9 + 2pq + 6q +6p

Please mark as brainliest answer.