Math, asked by vedharatchana15, 26 days ago

(p+q) = 8 and pq= 12, so what is the value of (p - q)​

Answers

Answered by NITESH761
1

Answer:

0

Step-by-step explanation:

p=8-q

so,pq=12

(8-q)q=12

8q-q²=12

q²-8q+12=0

q=6 or 2

putting in eq 1

p=6 or 2

so p-q is 0

Answered by udaisingh7177
0

Answer:

we have:

p + q = 8 and pq = 12

(Now,

( p - q )^2 = ( p+q)^2 - 2pq

( p - q)^2 = 8^2 - 2× 12

( p - q)^2 = 64 -24 = 40

( p - q)^2 = 40

( p -q) = square root of 40

p -q) = 2× square root of 10.Ans.

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