P, Q & R form a right-angled triangle.
R, S & P lie on a straight line.
PS = SQ and
∠
SQR = 40°.
Work out
∠
RPQ, explaining each stage of your working in the comment box.
The diagram is not drawn accurately.
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Given :
- ∠SQR = 40°.
To Find :
- ∠RPQ
Solution :
In ∆ PQR
→ ∠RPQ + ∠RQP + ∠PRQ = 180°
→ ∠RPQ + (∠RQS + ∠PQS) + ∠PRQ = 180°
→ ∠RPQ + (40° + ∠PQS) + 90° = 180°
→ ∠RPQ + ∠PQS + 40° + 90° = 180°
→ 2∠RPQ + 130° = 180° [ ∠RPQ and ∠PQS are base angles of an isosceles triangle ]
→ 2∠RPQ = 50°
→ ∠RPQ = 50/2
→ ∠RPQ = 25°
Hence,
- ∠RPQ = 25°.
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