Math, asked by 17mfatima, 5 months ago

P, Q & R form a right-angled triangle.
R, S & P lie on a straight line.
PS = SQ and

SQR = 40°.
Work out

RPQ, explaining each stage of your working in the comment box.

The diagram is not drawn accurately.

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Answers

Answered by Anonymous
16

Given :

  • ∠SQR = 40°.

To Find :

  • ∠RPQ

Solution :

In ∆ PQR

→ ∠RPQ + ∠RQP + ∠PRQ = 180°

→ ∠RPQ + (∠RQS + ∠PQS) + ∠PRQ = 180°

→ ∠RPQ + (40° + ∠PQS) + 90° = 180°

→ ∠RPQ + ∠PQS + 40° + 90° = 180°

→ 2∠RPQ + 130° = 180° [ ∠RPQ and ∠PQS are base angles of an isosceles triangle ]

→ 2∠RPQ = 50°

→ ∠RPQ = 50/2

→ ∠RPQ = 25°

Hence,

  • ∠RPQ = 25°.
Answered by shamimdoly123
0

Answer:

16

Step-by-step explanation:

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