Question

p, q and r are in a cycle race of 4500 meters. p cycles twice as fast as q. r cycles 1/3rd as fast as q. r completes the race in 45 minutes. then where was q from the finishing line when p finished the race?

Answer 1

2250m far from phinished line

Answer 2

Answer:

distance of Q from finish line, when P completed the race =2250 meter

Step-by-step explanation:

given, total distance of the race = 4500 m

speed of P = 2× speed of Q

and, speed of Q = 3 × speed of R

R completed the race in 45 minutes

⇒ Q takes $\frac{1}{3}$rd of the time taken by R to complete the race = $\frac{1}{3}$ × 45

    = 15 minutes

also, given that, P is twice as fast as Q

⇒time taken by P to complete the race = $\frac{1}{2}$ × 15

    = 7.5 minutes

in 7.5 minutes, P will complete the race. that time Q will be $\frac{1}{2}$th of the distance from finishing line

⇒ distance of Q from finish line, when P completed the race = $\frac{4800}{2}$

   =2250 meter