Math, asked by ISOLATEDREX2202, 27 days ago

p, q and r are natural numbers. p + 3 = 3 + q = 1 + 2 + r Then which of the following equations is true? A p + q =5 B p + q + r = 8 C p - q = q - r D p - q - r = p + q

Answers

Answered by llsll00123456

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Answered by Afreenakbar

Answer:

The Correct option is B: p + q + r = 8.

Step-by-step explanation:

The values of p, q, and r may be determined using the knowledge that p + 3 = 3 + q = 1 + 2 + r.

We get that p - q = 0 from p + 3 = 3 + q,

indicating that p = q - 0 = q.

We obtain q = r - 2 by substituting this value of p into the second equation,

3 + q = 1 + 2 + r.

As a result,

p = q and q = r - 2 apply that p = r - 2.

We obtain r = p by substituting this value of p into the third equation,

1 + 2 + r = p + 3.

Hence, p = q = r - 2.

Now, We can change these values in the available options to determine whether equation is correct.

Option A: p + q = 5, which becomes r - 2 + r - 2 = 5, which is not possible for natural numbers.

So, this option is false.

Option B: p + q + r = 8, which becomes r - 2 + r - 2 + r = 8, which is true for r = 4.

Therefore, option B is true.

Option C: p - q = q - r, which becomes r - 2q + p = 0. This is not true in general.

So, option C is false.

Option D: p - q - r = p + q, which becomes -2r = 2q, which is not true for natural numbers.

So, option D is false.

Therefore, the only true equation is option B: p + q + r = 8.