Question

P,Q and R are successive even natural numbers in ascending order.five times R is eight more than seven times P.find Q.

Answer 1

Answer:

P=6 and Q=8

Step-by-step explanation:

Given:

P, Q and R are successive even natural numbers

Then,

P=2n

Q=2(n+1)

R=2(n+2)

Also, 5R=7P+8

⇒5(2(n+2))=7(2n)+8

⇒10(n+2)=14n+8

⇒10n+20=14n+8

⇒20-8=14n-10n

⇒12=4n

⇒n=3

P=2(3)=6

Q=2(3+1)=8

Answer 2

Q is 8.

Step-by-step explanation:

Since we have given that

Let P be 2x.

Let Q be 2x+2

Let R be 2x+4

Since Five times R is eight more than seven times P.

So, it becomes,

$5(2x+4)-7\times 2x=8\\\\10x+20-14x=8\\\\-4x=8-20\\\\-4x=-12\\\\x=3$

So, Q would be $2(3)+2=6+2=8$

Hence, Q is 8.

# learn more:

P, Q, and R are consecutive positive even integers in the ascending order.four times R is 4 more than five times P. what is the value of Q?​

https://brainly.in/question/11717153