p, q and r are the three basic numbers if the equation pq + pr = 80 and pq + qr = 425 are solved; So what is the value of p + q + r?
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Answer:
p, q & r are prime numbers.
Suppose pqr = 101(p + q + r)
Since 101 is a prime number, we take
r = 101
So, pq = p + q + 101
So, pq - p - q + 1 = 101 + 1
So, (p - 1)(q - 1) = 102 = 1*102
Taking p - 1 = 1 & q - 1 = 102
We get p = 2 & q = 103
Thus, for the three prime numbers 2, 101 &
103 the equation
2*101*103 = 101*(2 + 101 + 103) is true.
Step-by-step explanation:
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