Question

p, q and r are the three basic numbers if the equation pq + pr = 80 and pq + qr = 425 are solved; So what is the value of p + q + r?

Answer 1

Answer:

p, q & r are prime numbers.

Suppose pqr = 101(p + q + r)

Since 101 is a prime number, we take

r = 101

So, pq = p + q + 101

So, pq - p - q + 1 = 101 + 1

So, (p - 1)(q - 1) = 102 = 1*102

Taking p - 1 = 1 & q - 1 = 102

We get p = 2 & q = 103

Thus, for the three prime numbers 2, 101 &

103 the equation

2*101*103 = 101*(2 + 101 + 103) is true.

Step-by-step explanation: