Math, asked by 1234biku, 11 months ago

P,Q and R can do a work in 10,15 and 30 days respectively P works daily Q and R together join P on alternate days starting the first day in how many days will the work be done

Answers

Answered by manibellamkonda1
7

Answer:6 1/2

Step-by-step explanation:

Lcm=10,15,30=30

30 means 30parts

Starting p+q+r=30/10+30/15+30/30

P+Q+R=6

Alternat day only P=3

For 2 days=9 parts

6days=27 parts

Remaining 3 parts done by p+q+r=3/6day =1/2day

Total work done in 6 1/2 days

Similar questions