Math, asked by tanujkatyaldj, 7 months ago

P, Q and R together can do a work in 27 days. They together work for 17 days and after that R left the work and the remaining work is done by P and Q together in 16 ⅔ days. Work done by P in 4 days is equal to work done by R in 3 days. Then, Find time taken by P alone to do this work ?

Answers

Answered by keerthanap360
0

Step-by-step explanation:

Let the rate at which the do work be p, q and r respectively.

When they work together we know that the rates add up.

Or

p + q = 1/18

p + r = 1/12

q + r = 1/9

Subtract the second equation from the first we get:

p + r - (p - q) = 1/12 - 1/18 = 1/6(1/2 - 1/3) = 1/36

Or r - q = 1/36

Subtract this equation from the third equation:

q + r - (r - q) = 1/9 - 1/36

or 2q = 1/9(1 - 1/4) = 1/12 or q = 1/24

Therefore Q alone will take 24 days.

Answered by chandrahasapoojary2
0

Answer:

this answer was in my Samsung notes

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