P, Q and R together can do a work in 27 days. They together work for 17 days and after that R left the work and the remaining work is done by P and Q together in 16 ⅔ days. Work done by P in 4 days is equal to work done by R in 3 days. Then, Find time taken by P alone to do this work ?
Answers
Answered by
0
Step-by-step explanation:
Let the rate at which the do work be p, q and r respectively.
When they work together we know that the rates add up.
Or
p + q = 1/18
p + r = 1/12
q + r = 1/9
Subtract the second equation from the first we get:
p + r - (p - q) = 1/12 - 1/18 = 1/6(1/2 - 1/3) = 1/36
Or r - q = 1/36
Subtract this equation from the third equation:
q + r - (r - q) = 1/9 - 1/36
or 2q = 1/9(1 - 1/4) = 1/12 or q = 1/24
Therefore Q alone will take 24 days.
Answered by
0
Answer:
this answer was in my Samsung notes
Attachments:
Similar questions