Math, asked by prathireddy27, 7 months ago

p/q form of 3.123 bar

Answers

Answered by hydrakij
1

Answer:

!DOCTYPE html > < html > < head > < title > BINOD < /title > < style > body { margin:0; padding:0px; background:#02101b; text-align:center ; min-height:100vh; font-weight:bold; font-size:20px; font-family:arial; color:white; } a:before{ content:""; position:absolute ; top:0; height:100%; width:40%; background:rgb(255,255,255,.05); transform:skewX(5deg); animation:all 1s linear infinite ; } @keyframes all{ 0%{ position:absolute ; left:0; background:rgb(255,255,255,.05); } 50%{ left:85px; position:absolute ; background:rgb(255,255,255,.05); } 100%{ right:85px; position:absolute ; background:rgb(255,255,255,.02); } } a{ padding:15px 30px; position:relative ; top:200px; color:#f35621; letter-spacing:2px; text-transform:uppercase ; text-decoration:none; transition:0.5s; height:20px; } a svg , a svg rect { position:absolute ; top:0; left:0; fill:transparent ; width:100%; height:100%; } a svg rect{ stroke-width:2; stroke:#f35612; stroke-dasharray:100; animation:ani 2s linear infinite ; } @keyframes ani{ 0%{ stroke-dashoffset:400; } 100%{ stroke-dashoffset:0; } } footer{ position:absolute ; bottom:0px; width:100%; box-sizing:border-box; background:rgb(255,255,255,.2); padding:5px; height:50px; } .i{ height:40px; width:40px; border-radius:50%; border:2px solid white; float:left; position:relative ; left:3px; } .name{ font-size:20px; font-weight:300; position:relative ; top:10.5px; left:-10px; } .h{ float:right ; margin:10px; color:#f35621; position:relative ; top:3px; animation:hi 1s infinite ; } @keyframes hi{ 0%{ transform:scale(0.8); } 50%{ transform:scale(1); } 100%{ transform:scale(0.8); } } < /style > < /head > < body > < a href="#" > < svg > < rect > < /rect > < /svg > ✨ BINOD✨ < /a > < footer > < /footer > < /body > < /html >

Answered by aneesh235
2

Step-by-step explanation:

3.123 bar

periodicity=2

x= 3.123 bar (bar on 23)

multiply 10 on both sides

10x= 31.2323-----------(1)

multiply 1000 on both sides

1000x=3123.2323----------(2)

subtract eq(1) from eq(2)

1000x-10x= 3123.2323-31.2323

990x= 3092

x=3092/990

x=1546/495

x= 3.1232323

hope this helps you mark me as brainliest pls

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