Question

p q is a tangent to a circle with centre o at point p if ️ opq is an isoscles ️ then find angle oqp​
its a math prob

Answer 1

Answer:

answer is 45°

Acc. to question OP=PQ

So , by theorem

angle POQ = angle PQO

Angle OPQ is 90° as radius is perpendicular to tangent

By angle sum property of a triangle

angle PQO is 45°

Answer 2

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pq is tangent and Oq is radius

we know that tangent is perpendiculatr to radius

Angle Opq = 90°

Angle OPQ is isoceles

• OP = PQ

Angle OQP = Angle POQ

SO,

angle Oqp = 1/2 X 90°

= 45°

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