Question

(p-q)(p+q)+(q-r)(r+p)+(r-p)(r+p)=0​

Answer 1

Answer:

it's ans is

p^2-q^2+(r+p)[q-r+r-p]

(p-q)(p+q)-(r+p)(p-q)

(p-q)[ q-r]=0

then either p=q or q=r

Answer 2

Answer:

The answer is (p+q) (p+r) (q+r)