(p-q)(p+q)+(q-r)(r+p)+(r-p)(r+p)=0
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Answered by
10
Answer:
it's ans is
p^2-q^2+(r+p)[q-r+r-p]
(p-q)(p+q)-(r+p)(p-q)
(p-q)[ q-r]=0
then either p=q or q=r
Answered by
0
Answer:
The answer is (p+q) (p+r) (q+r)
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