Question

(p+q)(p²-pq+q²) is equal to​

Answer 1

Step-by-step explanation:

(p+q)(p2−pq+q2)

=(p+q)(p2+−pq+q2)

=(p)(p2)+(p)(−pq)+(p)(q2)+(q)(p2)+(q)(−pq)+(q)(q2)

=p3−p2q+pq2+p2q−pq2+q3

=p3+q3

Answer 2

Step-by-step explanation:

(p+q)(p^2-pq+q^2)

=p(p^2-pq+q^2)+q(p^2-pq+q^2)

=p^3-p^2q+pq^2+p^2q-pq^2+q^3

=p^3+q^3