Question

(P+q) (p2_q2) +( p_q) (p2+q2)

Answer 1

Step-by-step explanation:

(p+q) (p2-q2) + (p-q) (P2-q2)

{[P2 (p+q)] - [q2(p+q)] +[p2(p-q)] - [q2(p-q)]}

{[p2(p+q)-q2(p-q)] +[p2(p-q) - q2(p+q)]}

[P3+p2q - q2p + q3] +[p3 - p2q - q2p - q3]

2p3 +p2q-p2q +q3 - q3

2p3

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