P+Q+R=0 and ।P। = 8. ।Q। = 15 and ।R। =17angle between P and Qis
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Given :-
- P + Q + R = 0
- | P | = 8
- | Q | = 15
- | R | = 17
To find :-
- Angle between P and Q , θ = ?
Knowledge required :-
- Formula to find the magnitude of resultant of two vectors
magnitude of resultant of two vectors M and N is given by
| M + N |² = M² + N² + 2 MN cos θ
( where M , N are magnitudes of two vectors M and N and θ is the angle between vectors M and N )
Solution :-
As given
↣ P + Q + R = 0
↣ P + Q = - R
so,
↣ | P + Q | = | - R |
↣ | P + Q |² = | - R |²
using formula for calculating magnitude of resultant of two vectors
↣ P² + Q² + 2 PQ cos θ = R²
↣ (8)² + (15)² + 2 (8)(15) cos θ = (17)²
↣ 64 + 225 + 240 cos θ = 289
↣ 240 cos θ = 289 - 64 - 225
↣ 240 cos θ = 0
↣ cos θ = 0
↣ θ = 90°
Therefore,
Angle between vectors P and Q is 90 degrees .
Note : In the Answer Bold letters P and Q are representing vectors and simple letters P and Q are representing magnitude of vectors P and Q.
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