Question

p-q+r=0 then the zeroes of the polynomial is px^2+qx+r is
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Answer 1

Answer:

Here is your answer

Step-by-step explanation:

Let α+iβ,α−iβ be the roots.

⇒ (α+iβ)(α−iβ)=

p

r

Then α

2

+β

2

=

p

r

>0.

So, p,r are of the same sign.

Also p+r>0.

So, p,r are both positive.

If q<0,p−q+r>0.

If q>0,(p+r)

2

−(p−r)

2

=4pr≥q

2

(∵ Roots are non-real).

∴(p+r)

2

≥q

2

+(p−r)

2

≥q

2

∴p+r>q