Question

(p-q-r)^2 what is the identity
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Answer 1

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Answer 2

Answer:

${(x + y + z) }^{2} = {x}^{2} + {y}^{2} + {z}^{2} + 2xy + 2xz + 2yz$

${(p - q - r)}^{2} = {p}^{2} + {( - q)}^{2} + {( - r)}^{2} - 2pq -2 pr + 2qr$

Step-by-step explanation:

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