Question

P+q+r=6,pq+qr+rp=5 and find value of p3+q3+r3-3pqr

Answer 1

$\huge \boxed{ \mathbb{ \ulcorner ANSWER: \urcorner}}$


Given:-)

→ p + q + r = 6.

→ pq + qr + rp = 5.



To Find :-)

→ p³ + q³ + r³ - 3pqr.


▶ We have,

=> p + q + r = 6.

[ Squaring both side ]


=> ( p + q + r ) ² = 6².

=> p² + q² + r² + 2 ( pq + qr + rp ) = 36.

=> p² + q² + r² + 2 ( 5 ) = 36.

=> p² + q² + r² + 10 = 36.

=> p² + q² + r² = 36 - 10.

=> p² + q² + r² = 26.


▶Now,

=> p³ + q³ + r³ - 3pqr = ( p + q + r ) ( p² + q² + r² - ( pq + qr + rp ) ).

= ( 6 ) ( 26 - (5) ).

= 6 × 21.

= 126.



✔✔Hence, it is solved ✅✅.

____________________________________




$\huge \boxed{ \mathbb{THANKS}}$



$\huge \bf{ \# \mathbb{B}e \mathbb{B}rainly.}$

Answer 2

$\huge \bf{hey}$


$\huge{ \mathfrak{here \: is \: answer}}$


$\bf{see \: in \: pic}$

$\huge \boxed{hope \: it \: helps}$


$\huge{ \mathbb{THANKS}}$