Math, asked by anushaarer248, 2 months ago

p.q.r & S are parallel terms r - q =? please Explain me​

Answers

Answered by jeevankishorbabu9985
2

Answer:

⇒  PQRS is trapezium. \\ </p><p></p><p>⇒   SP∥RQ           [ Given ] \\ </p><p></p><p>We \:  know, \:  sum \:  of  \: two  \: angles \:  between  \: parallel \:  lines \:  is  \: supplementary</p><p></p><p>

 \pink{ \huge \cal ∴   ∠QRS+∠RSP={180 }^{ o  }}

 {\huge {\frak {\green{⇒  ∠QRS+{90 }^{ o}={180 }^{o}}}}}

 \huge {\mathcal {\purple{⇒  ∠QRS={180 }^{ o}−{90 }^{ o}={90 }^{ o}}}}

 {\huge \bf⇒  ∠PQR+∠QRS+∠RSP+∠SPQ={360 }^{ o}}</p><p></p><p>

  \huge \sf\purple{⇒  {100 }^{ o}+{90 }^{o}+{90 }^{ o}+∠SPQ={360 }^{ o}}</p><p></p><p>

  \huge\red{ \bf ⇒  {280 }^{ o}+∠SPQ={360 }^{o}}</p><p></p><p>

  \sf\orange{⇒  ∠SPQ={360 }^{ o}−{280 }^{ o}={80 }^{ o}}</p><p></p><p>

 \color{cyan}∴   Measures \:  \:   \:  \: of  \:  \:  \: ∠P  \:  \:  \: and \:  \:  ∠R  \:  \:  \: are  \:  \: {80 }^{o  }\:  \: and  \:  \: {90 }^{ o }

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