P,Q,R are the midpoints of sides of triangle ABC respectively.Find the ratio of perimeters of triangle PQR and triangle ABC.
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Answered by
15
Given,
P , Q, R are midpoints of AB, BC and CA respectively.
Please refer attached image:
Hence,
[tex] \frac{Perimeter of triangle ABC}{Perimeter of triangle PQR} = \frac{2}{1} = 2:1 [/tex]
P , Q, R are midpoints of AB, BC and CA respectively.
Please refer attached image:
Hence,
[tex] \frac{Perimeter of triangle ABC}{Perimeter of triangle PQR} = \frac{2}{1} = 2:1 [/tex]
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Answered by
11
Solution :-
P, Q and R are the midpoints of sides AB, BC and AC of triangle ABC.
By mid point theorem,
⇒ PR = 1/2 of BC = PR/BC = 1/2......(1)
⇒ PQ = 1/2 of AC = PQ/AC = 1/2 .....(2)
⇒ QR = 1/2 of AB = QR/AB = 1/2 ......(3)
Hence, Perimeter of Δ ABC/Perimeter of Δ PQR
= (AB + BC + CA)/(PQ + QR + RP)
= (AB + BC + AC)/1/2(AB + BC + AC)
= 1/2
Answer.
P, Q and R are the midpoints of sides AB, BC and AC of triangle ABC.
By mid point theorem,
⇒ PR = 1/2 of BC = PR/BC = 1/2......(1)
⇒ PQ = 1/2 of AC = PQ/AC = 1/2 .....(2)
⇒ QR = 1/2 of AB = QR/AB = 1/2 ......(3)
Hence, Perimeter of Δ ABC/Perimeter of Δ PQR
= (AB + BC + CA)/(PQ + QR + RP)
= (AB + BC + AC)/1/2(AB + BC + AC)
= 1/2
Answer.
Golda:
it is 2/1 instead of 1/2.
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