Question

p q r s and t are consecutive numbers in increasing order. the sum of r and t is 184 . find p please do answer this question,

Answer 1

Hope it will help you.

Answer 2

p < q < r < s < t [Consecutive no. in increasing order - Keeps increasing by 1]

∴ t = r + 2                    →1              

Given :- sum of r and t is 184.

⇒ r + t = 184

r + r + 2 = 184                               [From 1]

   2r + 2 = 184

         2r = 184 - 2

           r = 182 ÷ 2

     ∴ r = 91

∴ For finding q, subtract 1 from r

q = r - 1

 = 90

We know that p is lesser than q by 1.

∴ p = q - 1

     = 90 - 1

∴ p = 89