Question

P,Q,S ARE SIBLINGS FOUR YEARS AGO P AGE WAS FOURTEEN LESS THAN TWICE THE THE SUM OF Q AND R SIX YEARS HENCE P AGE WILL BE FOUR LESS THAN THE SUM OF AGE OF Q AND R FIND THE AGE OF P

Answer 1

Step-by-step explanation:

Please check the question once again

whether it is in right way

Answer 2

Answer:

p = 30

Step-by-step explanation:

present age of p = p

present age of q = q

present age of r = r,

Four years ago,

p= p-4

q= q-4

r= r-4

ATQ.

p-4 = 2(q-4 + r-4) - 14.

let (q + r) = a

p-4=2(a-8) - 14.

p-2a+26=0 (1).

Six years hence,

p= p+6

q= q+6

r= r+6

p+6 = (a+12) - 4.

p-a-2=0 (2)

subtract equation 1 from equation 2.

p-2a+26=0

p- a - 2. = 0

_________

a + 28 =0, a = 28

__________

substitute a = 28 in question 1 or 2

p - a - 2 = 0

p - 28 - 2 = 0

p -30 = 0

p= 30

therefore the present age of P is 30 years.

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