p,q.x. are the lenths of the sides of triangle PQX respectively. if p-q=1find the value of x in terms of q.
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The given triangle is a right angled triangle
Therefore, x^2 + q^2 = p^2
p^2 - q^2 = x^2
(p-q)(p+q) = x^2................(1)
Given, p-q = 1...............(2)
p=1+q................(3)
Using (2) and (3) in (1), we get
1(1+1+q) = x^2
2+q = x^2
x = (2+q)^1/2
(x = square root of (2+q))
Hope it helps!
Thankyou :)
Therefore, x^2 + q^2 = p^2
p^2 - q^2 = x^2
(p-q)(p+q) = x^2................(1)
Given, p-q = 1...............(2)
p=1+q................(3)
Using (2) and (3) in (1), we get
1(1+1+q) = x^2
2+q = x^2
x = (2+q)^1/2
(x = square root of (2+q))
Hope it helps!
Thankyou :)
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