Question

p,q.x. are the lenths of the sides of triangle PQX respectively. if p-q=1find the value of x in terms of q.

Answer 1

The given triangle is a right angled triangle
Therefore, x^2 + q^2 = p^2
                 p^2 - q^2 = x^2
                 (p-q)(p+q) = x^2................(1)

Given, p-q = 1...............(2)
            p=1+q................(3)
Using (2) and (3) in (1), we get
                 1(1+1+q) = x^2
                   2+q = x^2
                   x = (2+q)^1/2 
(x = square root of (2+q))

Hope it helps!
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