p q x² – (p² + q²) x + p q = 0
Answers
Answered by
2
Answer:
P=5
Q = 9
Step-by-step explanation:
Answered by
0
Answer:
Step-by-step explanation:
pqx2 - (p2+q2)x +pq =0
a= pq, b= (p2+q2) c=pq
b2+-√D/2a.
+- means plus or minus
D= (p2+q2)^2- 4(pq)(pq)
(p2+q2)^2- 4(pq)2
{(P2+q2)^2+-√(p2+q2)^2-(2pq)^2}/2pq=0
p2+q2+-2pq =0
p2+q2+2pq =0 or p2+q2-2pq =0
(p+q)^2 or (p-q)^2
The roots of the equation are (p+q)^2 or (p-q)^2
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