Question

P,Qand R are the interaction points of bisector of internal angle B and Cbof triangle ABC, triangle PBC and triangle QBc. if angle A =60 degree then angle p +q+r is​

Answer 1

Answer:

∠ABC+ext.∠∠ABC=180

o

(Angles on a straight line)

2

1

(∠ABC+ext.∠ABC)=90

o

∠PBC+∠QBC=90

o

(PB bisect Interior ∠B, QB bisects ext.∠B)

∠PBQ=90

o

Similarly, ∠PCQ=90

o

Sum of angles of quadrilateral PBCQ =360

o

∠BPC+∠PBQ+∠PCQ+∠BQC=360

o

∠BPC+∠BQC=180

o

∴∠BPQ+∠BQC = 2 rt. angles

Step-by-step explanation:

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