Question

P,R are points on the side AB of triangle ABC. such that AP=4cm, PR=3cm, RB=5cm, lines through P and R parallel BC meet AC at Q and respectively, AQ=3 ,area of triangle ABC = 48 cm square hence find area triangle APQ.​

Answer 1

Answer:

In △ABC, PQ∥BC

So, by proportionality theorem

PB

AP

=

QC

AQ

=

BC

PQ

6

4

=

QC

AQ

=

BC

3

⇒

6

4

=

BC

3

∴ BC=4.5cm

solution

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