Question

P rove that

sec²θ + cosec²θ = (sec²θ) (cosec²θ)​

Answer 1

Step-by-step explanation:

The complete answer is given in the attached image

Answer 2

sec²θ + cosec²θ = (sec²θ) (cosec²θ)

LHS = sec²θ + cosec²θ =

1. 1. cos²x+sin²x. 1

------. + ---------- = -------------------- = ------------------

cos²x. sin² x cos²xsin²x cos²xsin²x

= sec²x × cosec²x