Question

p=rs.21600 rs=40 t=2 years calculate compound interest​

Answer 1

Answer :-

Given :-

• Principal = Rs. 21600
• Rate of interest = 40% p.a.
• Time = 2 years

To Find :-

• Compound interest

Solution :-

We know that,

$\sf A = P ( 1 + \frac{R}{100})^n$

Substituting the values :-

➩ $\sf A = 21600 \times ( 1 + \frac{40}{100})^2$

➩ $\sf A = 21600 \times ( \frac{14\cancel0}{10\cancel0})^2$

➩ $\sf A = 216\cancel{00} \times \frac{196}{1\cancel{00}}$

➩ $\sf A = 216 \times 196$

➩ $\sf A = 42336$

Amount = Rs. 42336

We know that,

Compound interest = Amount - Principal

= 42336 - 21600

= 20736

Compound interest = Rs. 20736