Question

P's age is twice of Q ,Q's age is twice of R and R's age is twice of S.If the average of the ages of P,Q,R andS is 15 years ,then what is the sum of the present ages of Q and S?

Answer 1

$\huge\red{Answer\: is}$

Here is your answer

Let the age of S is x years

Age of R is = 2x years

Age of Q is. = 2 × 2x = 4x years

Age of P is. = 2 × 4x = 8x years

Sum of P, Q, R and S is
$= x + 2x + 4x + 8x \\ = 15x$
Average age is 15 years

As we know the formula

Average = Sum of age / Total. Number
$15 = \frac{15x}{4} \\ 15x = 15 \times 4 \\ x = \frac{15 \times 4}{15} \\ x = 4$
Now
Age of Q is = 4 × 4
= 16 years

Age of S is = 4 years

Sum of age of Q and S is = 4+ 16

=20 years

$<marquee>Hope it helps you$