P sells a bag to Q at profit 20% Q decides to sell it to R ar profit 25%. If R pays Rs. 255/- fr it. Find the cp of the bag for P
Answers
Answered by
1
P buys at ?
P sells at 20% profit.
Q buys at ?
Q sells at 25%profit i.e 255.
Let CP to Q be 'x'
We know that,
profit=SP-CP=255-x
and,
Profit%=(profit/CP)×100
25={(255-x)/x}×100
25x=25500-100x
x=25500/125
x=204
Hence CP to Q=Rs204
Now,
let CP to P be 'y'.
Profit=204-y
and,
profit%=(profit/CP)×100
20={(204-y)/y}×100
20y=20400-100y
y=20400/120
y=170
Hence CP to P =Rs170
P sells at 20% profit.
Q buys at ?
Q sells at 25%profit i.e 255.
Let CP to Q be 'x'
We know that,
profit=SP-CP=255-x
and,
Profit%=(profit/CP)×100
25={(255-x)/x}×100
25x=25500-100x
x=25500/125
x=204
Hence CP to Q=Rs204
Now,
let CP to P be 'y'.
Profit=204-y
and,
profit%=(profit/CP)×100
20={(204-y)/y}×100
20y=20400-100y
y=20400/120
y=170
Hence CP to P =Rs170
gani123:
the other one said that 173 is correct bt which is correct Answer?
170 not 173 bro.
ya 170 bro
thnx
now its correct
Answered by
2
Rs. 170 is the cost price of the bag.
R = Q + 25% = 125%
255 = Q + 25%
Q = 255 - 25%
Q = 255x100/125
=> Q = 204
Q = P + 20% = 120%
204 = P + 20%
P = 204 - 20%
P = 204x100/120
=> P = 170
hence, cost price is Rs. 170
R = Q + 25% = 125%
255 = Q + 25%
Q = 255 - 25%
Q = 255x100/125
=> Q = 204
Q = P + 20% = 120%
204 = P + 20%
P = 204 - 20%
P = 204x100/120
=> P = 170
hence, cost price is Rs. 170
you can calculate according to 170.
you will get the answee
ok thanks
170 +20% = 170+34 = 204
hm ok
204 + 25% =204+51 = 255
hence 170 is CP
can u notify mistake in my answer
Thanks
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