Math, asked by vidishaagrawal, 1 year ago

(P square - 2pq + q square) - r square × s square

Answers

Answered by Niharikamishra24
5

Question:-

(P square - 2pq + q square) - r square × s square

{\pink{\underline{\underline{\bold{Answer:-}}}}}

P^2q - pr^2 - pq + r^2

=P × (pq-r^2)-(pq- r^2)

=(Pq-r^2) × (p-1).......

hope it helps you..

Answered by Anonymous
74

Answer:

(P square - 2pq + q square) - r square × s square

{\pink{\underline{\underline{\bold{Answer:-}}}}}

P^2q - pr^2 - pq + r^2

=P × (pq-r^2)-(pq- r^2)

=(Pq-r^2) × (p-1).......

Step-by-step explanation:

Similar questions