P.T: (1 + ^2) + (1 + 1 /tan ) = 1/ ^2−^4A
Answers
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Step-by-step explanation:
Identity : sec
2
A−tan
2
A=1
LHS=(1+tan
2
A)(1+
tan
2
A
1
)
=(sec
2
A)
tan
2
A
sec
2
A
=
cos
2
A
1
cos
2
A
sin
2
A
cos
2
A
1
=
sin
2
Acos
2
A
1
=
sin
2
A(1−sin
2
A)
1
=
sin
2
A−sin
4
A
1
=RHS
Hence proved
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