Math, asked by kitshan78, 5 days ago

p(t) =2+t+2t^-t3
answer what​

Answers

Answered by Anonymous
4

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P(t) = 2 + t + 2t²-t3 then the values of P(0),P(1),P(2) are respectively

P(t) = 2+ t+ 2t² - t3

P(0)=2+0+2 \times 0² - 0 \times 3

=2

P(1) = 2 + 1 + 2

 \times 1² - 1 \times 3

=4

P(2) = 2 + 2 + 2 \times 2² - 2 \times 3

= 9

Answered by sahuvedram969
0

Answer:

Answer is the attached with the photo

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