Math, asked by sumaira55, 8 months ago

p.t 3a+2/4×3a-3a+1/3a=2 ( exponents)
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Answers

Answered by trupthi8
5

Answer:

(3a+1)(3a−2)(3a+4)

\mathrm{Expand}\:(3a+1)(3a-2)Expand(3a+1)(3a−2)

(3a+1)(3a-2)(3a+1)(3a−2)

\mathrm{Apply\:FOIL\:method}:\quad (a+b)(c+d)=ac+ad+bc+bdApplyFOILmethod:(a+b)(c+d)=ac+ad+bc+bd

a=3a,\:b=1,\:c=3a,\:d=-2a=3a,b=1,c=3a,d=−2

=3a\cdot \:3a+3a(-2)+1\cdot \:3a+1\cdot (-2)=3a⋅3a+3a(−2)+1⋅3a+1⋅(−2)

\mathrm{Apply\:minus-plus\:rules}Applyminus−plusrules

+(-a)=-a+(−a)=−a

=3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:2=3⋅3aa−3⋅2a+1⋅3a−1⋅2

\mathrm{Simplify}\:3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:2Simplify3⋅3aa−3⋅2a+1⋅3a−1⋅2

3\cdot \:3aa-3\cdot \:2a+1\cdot \:3a-1\cdot \:23⋅3aa−3⋅2a+1⋅3a−1⋅2

3\cdot \:3aa3⋅3aa

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:3=9Multiplythenumbers:3⋅3=9

=9aa=9aa

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}Applyexponentrule:a

b

⋅a

c

=a

b+c

aa=\:a^{1+1}aa=a

1+1

=9a^{1+1}=9a

1+1

\mathrm{Add\:the\:numbers:}\:1+1=2Addthenumbers:1+1=2

=9a^2=9a

2

3\cdot \:2a=6a3⋅2a=6a

1\cdot \:3a=3a1⋅3a=3a

1\cdot \:2=21⋅2=2

=9a^2-6a+3a-2=9a

2

−6a+3a−2

=(9a^2-3a-2)(3a+4)=(9a

2

−3a−2)(3a+4)

\mathrm{Expand}\:(9a^2-3a-2)(3a+4)Expand(9a

2

−3a−2)(3a+4)

(9a^2-3a-2)(3a+4)(9a

2

−3a−2)(3a+4)

\mathrm{Distribute\:parentheses}Distributeparentheses

=9a^2\cdot \:3a+9a^2\cdot \:4+(-3a)\cdot \:3a+(-3a)\cdot \:4+(-2)\cdot \:3a+(-2)\cdot \:4=9a

2

⋅3a+9a

2

⋅4+(−3a)⋅3a+(−3a)⋅4+(−2)⋅3a+(−2)⋅4

\mathrm{Apply\:minus-plus\:rules}Applyminus−plusrules

+(-a)=-a+(−a)=−a

=9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:4=9⋅3a

2

a+9⋅4a

2

−3⋅3aa−3⋅4a−2⋅3a−2⋅4

\mathrm{Simplify}\:9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:4Simplify9⋅3a

2

a+9⋅4a

2

−3⋅3aa−3⋅4a−2⋅3a−2⋅4

9\cdot \:3a^2a+9\cdot \:4a^2-3\cdot \:3aa-3\cdot \:4a-2\cdot \:3a-2\cdot \:49⋅3a

2

a+9⋅4a

2

−3⋅3aa−3⋅4a−2⋅3a−2⋅4

9\cdot \:3a^2a9⋅3a

2

a

\mathrm{Multiply\:the\:numbers:}\:9\cdot \:3=27Multiplythenumbers:9⋅3=27

=27a^2a=27a

2

a

\mathrm{Apply\:exponent\:rule}:\quad \:a^b\cdot \:a^c=a^{b+c}Applyexponentrule:a

b

⋅a

c

=a

b+c

a^2a=\:a^{2+1}a

2

a=a

2+1

=27a^{2+1}=27a

2+1

\mathrm{Add\:the\:numbers:}\:2+1=3Addthenumbers:2+1=3

=27a^3=27a

3

9\cdot \:4a^2=36a^29⋅4a

2

=36a

2

3\cdot \:3aa=9a^23⋅3aa=9a

2

3\cdot \:4a=12a3⋅4a=12a

2\cdot \:3a=6a2⋅3a=6a

2\cdot \:4=82⋅4=8

=27a^3+36a^2-9a^2-12a-6a-8=27a

3

+36a

2

−9a

2

−12a−6a−8

\mathrm{Add\:similar\:elements:}\:-12a-6a=-18aAddsimilarelements:−12a−6a=−18a

=27a^3+36a^2-9a^2-18a-8=27a

3

+36a

2

−9a

2

−18a−8

\mathrm{Add\:similar\:elements:}\:36a^2-9a^2=27a^2Addsimilarelements:36a

2

−9a

2

=27a

2

=27a^3+27a^2-18a-8=27a

3

+27a

2

−18a−8

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