p t √5 is a irrational number
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let root 5 be rational
there for √3=a/b.(a and b are integer and not equal to 0)
suppose a and b have have common factor other than 1,then we can divide by the common factor, and asume that a and bare coprime.
so, b√3=a.
on squaring both side we get,
3b^2=a^2.
thereforea^2is divisible by 3and b is also divisible by 3
therefore a and b have at least 3 as common factor.
But this contradicts the fact a and b are coprime.
This contradiction arises due to our wrong assumption.
Therefore√3 is irritional.
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