Question

p(t) = 6t^3 +3t^2+3t+18 is a multiple of (2t+3).
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Answer 1

hope this helps you.. :)

Answer 2

T=-3/2

P(-3/2)=6(-3/2)^3+3(-3/2)^2+3(-3/2)+18

-81/4+27/4-9/2+18

-81+27-18+72/4

99-99/4

0/4

=0