Question

P(t) = 6t^3+3t^2+3t+18 is a multiple of (2t+3)

Answer 1

Answer:

put t=1 then substitute in both

2(1)+3=5

6(1)+3(1)+3(1)+18=30

30 is a multiple of 5

put t=2,3,4,5......

6t^3+3t^2+3t+18 is a multiple of (2t+3)