P,T are the centers of two circles joining internal.proove At parallel SP
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Let the centre of the circle be O.
AB = 12 cm
OC = 12 cm
OC ⊥ AB
We know perpendicular drawn from the centre of the circle to the chord, bisects the chord.
So, AC = 6 cm
In ⃤ OCA,
OC2+AC2=AO2⇒82+62=AO2⇒AO2=100⇒AO=10
Thus, AO = 10 cm
Diameter = 2 × 10 cm = 20 cm.
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