P.T : cosec²Q+sec²Q=cosec²Q sec²Q
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Answer:
to prove cosec² x + sec² x = cosec² x sec² x
=> LHS
=> 1/sin² x + 1/cos² x
=> (cos² x + sin² x) / sin² x cos² x [ taking LCM ]
=> 1/sin² x cos² x [ sin²x + cos²x = 1 ]
=> 1/sin² x × 1/cos² x
=> cosec² x sec² x = RHS
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