Question

P.t. (sec A + tan A)square = 1 + sin A upon 1-sin A

Answer 1

(secA+tanA)² =1+sinA/1-sinA

(1/cosA + sinA/cosA)² = RHS

(1+sinA/cosA)² = RHS

(1+sinA)² /cosA² =RHS

(1+sinA)² /1-sinA² =RHS

(1+sinA)(1+sinA)/ (1-sinA)(1+sinA) = RHS

1+sinA/1-sin = RHS