Question

p(t) = (t-1) (t+1) find p(0),p(1)and p(2)

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Answer 1

hope this helps u

Step-by-step explanation:

(t-1) (t+1)  is in the form of [a-b] [a+b] = a²-b²

so we will write as p(t) = t²-1²

p(0) = 0²-1²

        = 0-1

p(0) = -1

p(1) = 1²-1²

     = 1-1

p(1) = 0

p(2) = 2²-1²

       = 4-1

       = 3

Answer 2

Answer:

p(t)= (t-1)(t+1)

on putting the values of 't' , we get

when t=0,

p(0)=(0-1)(0+1)

p(0)= -1 . 1

p(0)= -1

when t=1,

p(1)= (1-1)(1+1)

p(1)=0.2

p(1) =0

when t=2,

p(2)=(2-1)(2+1)

p(2)= 1 . 3

p(2) =3

hope it's helpful for you..............