Question

p(t)=t³-6x²+11x-6
the value of t=?
​

Answer 1

Given :

p(t)=t³-6x²+11x-6

To find :

p(-1)

p(-2)

p(2)

p(3)

p(1)

Solution :

p(t)=t³-6x²+11x-6

p(-1)=(-1)³-6(-1)²+11(-1)-6

= -1 -6 -11 -6

= -12-12

= -24

So first option is wrong.

p(2)=(2)³-6(2)²+11(2)-6

= 8 - 24 +22 -6

= 0

So, second one is also wrong.

p(-2)=(-2)³-6(-2)²+11(-2)-6

= -8 -24 -22 -6

= -60

Even third one is wrong.

p(1)=1³-6(1)²+11(1)-6

= 1 -6 +11 -6

= 0

p(3) = 3³ -6(3)² +11(3) -6

= 27 - 54 +33 -6

= 60 -60

= 0

p(1) = p(3)

Thus , correct option is (4).

Answer 2

$\huge\underline\bold\red{Answer:-}$

$\huge\underline\bold\red{Option/4}$

p(1) = p(3)

Thanks!